Solve a small-molecule structure

The following is based on the experience of a protein crystallographer who one day obtained a small-molecule dataset and managed to solve and refine it without prior knowledge what the crystallized substance was. It was a very rewarding experience which is why it's written up here.

This is just a case study. To understand things, one has to read http://shelx.uni-ac.gwdg.de/SHELX/shelx.pdf .

reduce the data with your favourite data processing software

I use XDS. The decision about the spacegroup has to be postponed, but it surely helps if the correct Laue group is employed during scaling. In the case considered here, the CORRECT step suggested P222.

convert the reflection file to HKLF 4 format (intensities!)

The HKLF 4 format is what the SHELX programs read. I used XDSCNV and the following 2-line XDSCONV.INP:

INPUT_FILE=XDS_ASCII.HKL
OUTPUT_FILE=temp.hkl

run XPREP to find out the spacegroup

answer the question concerning the cell axes, and then hit <Enter> several times until the program suggests a list of spacegroups - this choice is going to be important. It helps a bit to observe earlier whether it's centrosymmetric or not, from the line: Mean |E*E-1| = 0.939 [expected .968 centrosym and .736 non-centrosym]. After that, say "c" for "define unit-cell CONTENTS", and input a reasonable number of carbon atoms (I used C20). Get out of this menu with "E". Then, choose "f" for "set up shelxtl FILES". Then, answer the question "XM/SHELXD (M) or XS/SHELXS (S) format [S]:" with "m" since we're going to use shelxd for solving the structure. Answer the question about the name (I used the spacegroup number as I knew I would have to test several possibilities). Finally, "q"uit the program. The resulting 62.ins is:

TITL 62 in Pnma 
CELL 0.71073   8.4900  28.7000  14.4300  90.000  90.000  90.000
ZERR   11.00   0.0017   0.0057   0.0029   0.000   0.000   0.000
LATT  1
SYMM 0.5-X, -Y, 0.5+Z
SYMM -X, 0.5+Y, -Z
SYMM 0.5+X, 0.5-Y, 0.5-Z
SFAC C
UNIT 220
FIND    16
PLOP    22    27    31
MIND 1.0 -0.1
NTRY 1000
HKLF 4
END

solving the structure with SHELXD

Just run "shelxd 62". You may interrupt it with Ctrl-C once it has found good solutions, as evidenced by

Try 68:20  Peaks 99 96 71 68 63 55 53 51 50 48 46 45 45 44 44 43 43 43 41 40
R = 0.417, Min.fun. = 0.853, <cos> = 0.364, Ra = 0.432
Try    68, CC All/Weak 40.17 / 25.34, best 40.17 / 25.60, best final CC  0.00
Peaklist optimization cycle  1    CC = 46.01 %    BG = 0.638   for   21 atoms
Peaks: 99 91 66 63 63 55 54 49 49 45 43 43 42 42 41 39 20 18 18 17 17 -17   
Fragments: 7 4 4 3 1 1 1                                                     
Peaklist optimization cycle  2    CC = 52.55 %    BG = 0.593   for   25 atoms
Peaks: 99 94 85 74 73 73 70 70 66 64 64 63 62 62 61 60 60 60 59 59 57 24 -24
Fragments: 14 5 4 1 1                                                        
Peaklist optimization cycle  3    CC = 58.37 %    BG = 0.541   for   29 atoms
Peaks: 99 92 85 72 72 70 69 66 65 63 63 62 61 60 59 59 59 -58 58 58 57 57 56
Fragments: 17 7 4 1                                                          

and the resulting 62.res is:

REM TRY     77   FINAL CC 58.70   TIME       5 SECS
REM Fragments: 17 7 3 2 2
REM 
TITL 62 in Pnma
CELL 0.71073   8.4900  28.7000  14.4300  90.000  90.000  90.000
ZERR   11.00   0.0017   0.0057   0.0029   0.000   0.000   0.000
LATT  1
SYMM 0.5-X, -Y, 0.5+Z
SYMM -X, 0.5+Y, -Z
SYMM 0.5+X, 0.5-Y, 0.5-Z
SFAC C
UNIT 220
C001  1  0.15479  0.75000  0.04294 10.50000 0.1   99.00
C002  1  0.84807  0.75000 -0.04054 10.50000 0.1   77.20
C003  1  0.19291  0.85742 -0.17716 11.00000 0.1   63.76
C004  1  0.59349  0.82735  0.20939 11.00000 0.1   62.64
C005  1  0.84406  0.88664  0.13204 11.00000 0.1   61.71
C006  1  0.23705  0.75000 -0.14287 10.50000 0.1   61.63
C007  1  0.71260  0.88327  0.09698 11.00000 0.1   60.92
C008  1  0.65969  0.78420 -0.13163 11.00000 0.1   59.90
C009  1  0.33293  0.91881 -0.04193 11.00000 0.1   58.80
C010  1  0.84248  0.99455 -0.16293 11.00000 0.1   58.58
C011  1  0.33883  0.78497 -0.20937 11.00000 0.1   56.06
C012  1  0.78396  0.94630  0.02080 11.00000 0.1   55.98
C013  1  0.97651  0.99845 -0.10805 11.00000 0.1   55.35
C014  1  0.90340  0.82762 -0.12071 11.00000 0.1   55.25
C015  1  0.16673  0.90700  0.07074 11.00000 0.1   55.25
C016  1  0.71552  0.97497 -0.17793 11.00000 0.1   54.99
C017  1  0.77400  0.78674 -0.00654 11.00000 0.1   54.97
C018  1  0.18750  0.90013 -0.13125 11.00000 0.1   54.86
C019  1  0.43404  0.85828  0.15317 11.00000 0.1   54.85
C020  1  0.51732  0.82874  0.09415 11.00000 0.1   54.52
C021  1  0.99843  0.84427 -0.05892 11.00000 0.1   54.40
C022  1  0.64265  0.91301  0.04166 11.00000 0.1   54.11
C023  1  0.18994  0.90304 -0.02101 11.00000 0.1   53.98
C024  1 -0.00029  0.87744 -0.23364 11.00000 0.1   53.75
C025  1  0.30272  0.89035  0.02043 11.00000 0.1   53.54
C026  1  0.72766  0.95461 -0.10200 11.00000 0.1   51.40
C027  1  0.77380  0.96500  0.10122 11.00000 0.1   49.11
C028  1  0.39642  0.72972  0.17524 11.00000 0.1   24.76
C029  1  0.66918  0.82482  0.13969 11.00000 0.1   21.87
C030  1  0.28518  0.73520  0.01792 11.00000 0.1   21.39
C031  1  0.40533  0.78770  0.08494 11.00000 0.1   19.94
HKLF 4
END

Refinement in SHELXL

It makes sense to remove the last 4 atoms since their occupancy is less than 25%, and the final remaining atom then is at 49% - a large jump. Insert

ACTA
LIST 6
L.S. 10

after the UNIT 220 instruction, and run shelxl 62.