Renumber files: Difference between revisions
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(Created page with 'Let's say you have a list of images named something_###.img with ### spanning 381-560, and you want to renumber them to be from 1 to 180. '''echo | awk '{for(i=1;i<181;i++) prin…') |
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Let's say you have a list of images named something_###.img with ### spanning 381-560, and you want to renumber them to be from 1 to 180. | Let's say you have a list of images named something_###.img with ### spanning 381-560, and you want to renumber them to be from 1 to 180. | ||
== Bash/awk one-liner == | |||
echo | awk '{for(i=1;i<181;i++) printf "mv something_%03d.img something_%03d.img\n",i+380,i;}' | bash -sf | |||
will do it. Notice that "%03d" will make sure that numbers are padded with zeros (and if you need 4 digits total, just use %04d instead). Also, always pipe it to less first before piping to bash, just to make sure that you are not going to inadvertently delete something. | will do it. Notice that "%03d" will make sure that numbers are padded with zeros (and if you need 4 digits total, just use %04d instead). Also, always pipe it to less first before piping to bash, just to make sure that you are not going to inadvertently delete something. | ||
== Bash one-liner == | |||
c=1 && for f in something_{381..560}.img ; do mv $f something_`printf "%03d" "$c"`.img ; c=$(($c+1)) ; done | |||
== Bash script == | |||
#!/bin/bash | |||
# set your first desired image number | |||
c=1 | |||
# loop on the input file names. the {X..Y} is called brace expansion. | |||
for f in something_{381..560}.img ; do | |||
# infinitely useful printf as you noted | |||
mv $f something_`printf "%03d" "$c"`.img | |||
# increment the counter | |||
c=$(($c+1)) | |||
done # loop ends | |||
== Perl one-liner == | |||
perl -e 'for(<*>) {rename $_,$1.($2-380).$3 if /(.+?)(\d+)(.img)$/}' | |||
Back to [[Useful scripts (aka smart piece of code)]] | |||
Latest revision as of 16:04, 16 December 2010
Let's say you have a list of images named something_###.img with ### spanning 381-560, and you want to renumber them to be from 1 to 180.
Bash/awk one-liner[edit | edit source]
echo | awk '{for(i=1;i<181;i++) printf "mv something_%03d.img something_%03d.img\n",i+380,i;}' | bash -sf
will do it. Notice that "%03d" will make sure that numbers are padded with zeros (and if you need 4 digits total, just use %04d instead). Also, always pipe it to less first before piping to bash, just to make sure that you are not going to inadvertently delete something.
Bash one-liner[edit | edit source]
c=1 && for f in something_{381..560}.img ; do mv $f something_`printf "%03d" "$c"`.img ; c=$(($c+1)) ; done
Bash script[edit | edit source]
#!/bin/bash
# set your first desired image number
c=1
# loop on the input file names. the {X..Y} is called brace expansion.
for f in something_{381..560}.img ; do
# infinitely useful printf as you noted
mv $f something_`printf "%03d" "$c"`.img
# increment the counter
c=$(($c+1))
done # loop ends
Perl one-liner[edit | edit source]
perl -e 'for(<*>) {rename $_,$1.($2-380).$3 if /(.+?)(\d+)(.img)$/}'